document.write( "Question 836128: Hi, \r
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document.write( "I hope you can help. Many thanks for your time. Hugh\r
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document.write( "Make k the subject of each of the following two equations. Show each step
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document.write( "of your working.\r
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document.write( "Question A\r
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document.write( "2m=9t/5k−7\r
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document.write( "Question B\r
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document.write( "5k = 3t− 3k/t \n" );
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Algebra.Com's Answer #503965 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i suppose you mean to solve for k. \n" ); document.write( "let's take a look:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first problem: \n" ); document.write( "start with: \n" ); document.write( "2M = (9T / 5K) - 7 \n" ); document.write( "add 7 to both sides of this equation to get: \n" ); document.write( "2M + 7 = 9T / 5K \n" ); document.write( "multiply both sides of this equation by K to get: \n" ); document.write( "K * (2M + 7) = 9T / 5 \n" ); document.write( "divide both sides of this equation by (2M + 7) to get: \n" ); document.write( "K = 9T / (5 * (2M + 7)) \n" ); document.write( "you can simplify this further to get: \n" ); document.write( "K = 9T / (10M + 35) \n" ); document.write( "that's your answer. assuming your original equation is as shown above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second problem: \n" ); document.write( "start with: \n" ); document.write( "5K = 3T - (3K / T) \n" ); document.write( "multiply both sides of this equation by T to get? \n" ); document.write( "5KT = 3T^2 - 3K \n" ); document.write( "add 3K to both sides of this equation to get: \n" ); document.write( "5KT + 3K = 3T^2 \n" ); document.write( "factor out the K on the left side of this equation to get: \n" ); document.write( "K * (5T + 3) = 3T^2 \n" ); document.write( "divide both sides of this equation by (5T + 3) to get: \n" ); document.write( "K = 3T^2 / (5T + 3) \n" ); document.write( "that's your answer, assuming your original equation is as shown above. \n" ); document.write( "I don't believe it can be simplified any further.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |