document.write( "Question 836105: Divide 59 into two parts so that one part is 7 less than 5 times the other part. \n" ); document.write( "
Algebra.Com's Answer #503956 by LinnW(1048)\"\" \"About 
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x = first number
\n" ); document.write( "y = second number
\n" ); document.write( "x + y = 59
\n" ); document.write( "x = 5y - 7
\n" ); document.write( "substitute (5y -7) for x in x + y = 59
\n" ); document.write( "(5y -7) + y = 59
\n" ); document.write( "6y -7 = 59
\n" ); document.write( "add 7 to each side
\n" ); document.write( "6y = 66
\n" ); document.write( "divide each side by 6
\n" ); document.write( "y = 11
\n" ); document.write( "Since x = 5y -7
\n" ); document.write( "x = 5(11) - 7
\n" ); document.write( "x = 55 -7
\n" ); document.write( "x = 48
\n" ); document.write( "So our numbers are 11 and 48 \n" ); document.write( "
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