document.write( "Question 836033: Four times the smaller of two consecutive odd integers is the same as 73 less than 5 times the larger. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #503943 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
Here's what the problem tells us:
\n" ); document.write( "The numbers are A B
\n" ); document.write( "B = A + 2 (consecutive odd)
\n" ); document.write( "4B = 5A - 73
\n" ); document.write( ".
\n" ); document.write( "Substitute the value of B into the second equation
\n" ); document.write( "4(A+2) = 5A - 73
\n" ); document.write( "Distribute
\n" ); document.write( "4A + 8 = 5A -73
\n" ); document.write( "Subtract 4A from each side
\n" ); document.write( "8 = A - 73
\n" ); document.write( "Add 73 to each side
\n" ); document.write( "81 = A
\n" ); document.write( "
\n" );