document.write( "Question 836033: Four times the smaller of two consecutive odd integers is the same as 73 less than 5 times the larger. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #503943 by JulietG(1812) You can put this solution on YOUR website! Here's what the problem tells us: \n" ); document.write( "The numbers are A B \n" ); document.write( "B = A + 2 (consecutive odd) \n" ); document.write( "4B = 5A - 73 \n" ); document.write( ". \n" ); document.write( "Substitute the value of B into the second equation \n" ); document.write( "4(A+2) = 5A - 73 \n" ); document.write( "Distribute \n" ); document.write( "4A + 8 = 5A -73 \n" ); document.write( "Subtract 4A from each side \n" ); document.write( "8 = A - 73 \n" ); document.write( "Add 73 to each side \n" ); document.write( "81 = A \n" ); document.write( " |