document.write( "Question 836065: I simply dont understand how to switch from the identites and solve these sort of questions...
\n" ); document.write( "Prove the following identities:
\n" ); document.write( "Cos^4 A + sin^4 A + 2sin^2 Ax cos^2 A =1
\n" ); document.write( "CosA -sinA/ cos A+sinA = 1-2sinAcosA/1-2sin^2A
\n" ); document.write( "CosA/sqroot(1+tanA) + sinA/ sqroot (1+cot^2 A) =1\r
\n" ); document.write( "\n" ); document.write( "Please help, thank you,!
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Algebra.Com's Answer #503940 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Prove the following identities:
\n" ); document.write( "Cos^4 A + sin^4 A + 2sin^2 Ax cos^2 A =1
\n" ); document.write( "Factor:
\n" ); document.write( "(cos^2+sin^2)(cos^2+sin^2) = 1
\n" ); document.write( "1*1 = 1
\n" ); document.write( "1 = 1
\n" ); document.write( "--------------------------------------------------
\n" ); document.write( "CosA -sinA/ cos A+sinA = 1-2sinAcosA/1-2sin^2A
\n" ); document.write( "Left side: Multiply numerator and denominator by cos-sin
\n" ); document.write( "Right side: In place of \"1\" put sin^2+cos^2
\n" ); document.write( "---
\n" ); document.write( "(cos-sin)^2/(cos^2-sin^2) = [sin^2 -2sin*cos +cos^2]/(1-2sin^2)
\n" ); document.write( "-------
\n" ); document.write( "Notice that the numerators are the same
\n" ); document.write( "Notice that the denominators are the same
\n" ); document.write( "-------
\n" ); document.write( "(cos^2-2cos*sin+sin^2)/(1-2sin^2) = (cos^2-2sin*cos+sin^2)/(1-2sin^2
\n" ); document.write( "==================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "------\r
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