document.write( "Question 835987: A brewer's spent grain contains 80 percent (m/m) moisture. When the grain has lost half of its weight, what is the moisture content? \n" ); document.write( "
Algebra.Com's Answer #503907 by josgarithmetic(39618)\"\" \"About 
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100 parts of spent grain.\r
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\n" ); document.write( "\n" ); document.write( "(80 parts moisture)/(100 parts spent grain)
\n" ); document.write( "Plenty of moisture to lose.\r
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\n" ); document.write( "\n" ); document.write( "\"%2880-50%29%2F%28100-50%29\", because half of the 100 parts is 50 parts.
\n" ); document.write( "Computation: \"30%2F50=60%2F100\"
\n" ); document.write( "Result: 60% moisture.
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