document.write( "Question 835128: Ms. Dinero wants to invest $2,300 compounded annually for 6 years with a balance of $4,200 at the end of that time period. At what rate would she have to invest her money to achieve that goal? (Round to the nearest hundreth)\r
\n" ); document.write( "\n" ); document.write( "I set up the compound interest formula like this: 4200=2300(1+(x/1))^6 but don't know what to do after I divided each side by 2300. Help please! I can't figure out how to get the variable alone \n" ); document.write( "

Algebra.Com's Answer #503866 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"4200=2300%281%2B%28x%2F1%29%29%5E6\"$
\n" ); document.write( " $\"%281%2Bx%29%5E6=42%2F23\"$
\n" ); document.write( " $\"1%2Bx=%2842%2F23%29%5E%281%2F6%29\"$
\n" ); document.write( " $\"x=%2842%2F23%29%5E%281%2F6%29-1\"$
\n" ); document.write( "or approximately
\n" ); document.write( " $\"x=.10557\"$ \n" ); document.write( "

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