document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835930>Question 835930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in how much time will a certain sum be 1.5 times the principal at 10% per annum? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503821 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use <BR>\n" );
document.write( "(1) B = P(1+r)^t or<BR>\n" );
document.write( "(2) B/P = (1+r)^t<BR>\n" );
document.write( "The problem statement has <BR>\n" );
document.write( "(3) B/P = 1.5 and<BR>\n" );
document.write( "(4) r = 10% or <BR>\n" );
document.write( "(5) r = 0.10<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "(6) 1.5 = (1 + 0.10)^t or<BR>\n" );
document.write( "(7) 1.5 = (1.1)^t<BR>\n" );
document.write( "Now take the log or ln of both sides to get<BR>\n" );
document.write( "(8) ln(1.5) = t*ln(1.1) or<BR>\n" );
document.write( "(9) t = ln(1.5)/ln(1.1)<BR>\n" );
document.write( "Use a scientific calculator to evaluate (9), and get<BR>\n" );
document.write( "(10) t = 0.405/0.0953 or<BR>\n" );
document.write( "(11) t = 4.25416...<BR>\n" );
document.write( "Use (7) to check the value of t<BR>\n" );
document.write( "Is (1.5 = (1.1)^4.254..)?<BR>\n" );
document.write( "Is (1.5 = 1.5)? Yes<BR>\n" );
document.write( "Answer: It will take 4.25... years for the principal P to \"grow\" to 1.5 times P. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );