document.write( "Question 835814: if the digits of my present age are reversed then i get the age of my son.if 1 year ago my age was twice as that of my son.find my present age. \n" ); document.write( "
Algebra.Com's Answer #503808 by ankor@dixie-net.com(22740)\"\" \"About 
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let m = my present age
\n" ); document.write( "let s = son's present age
\n" ); document.write( ":
\n" ); document.write( "let a = my 10's digit
\n" ); document.write( "let b = my units digit
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\n" ); document.write( "if the digits of my present age are reversed then i get the age of my son.
\n" ); document.write( "m = 10a+b
\n" ); document.write( "s = 10b+a
\n" ); document.write( "if 1 year ago my age was twice as that of my son.
\n" ); document.write( "m-1 = 2(s-1)
\n" ); document.write( "m - 1 = 2s - 2
\n" ); document.write( "m = 2s - 2 - 1
\n" ); document.write( "m = 2s - 1
\n" ); document.write( "Replace m with (10a+b), replace s with (10b+a)
\n" ); document.write( "10a + b = 2(10b+a) - 1
\n" ); document.write( "10a + b = 20b + 2a - 1
\n" ); document.write( "10a - 2a = 20b - b - 1
\n" ); document.write( "8a = 19b - 1
\n" ); document.write( "a = \"19%2F8\"b - \"1%2F8\"
\n" ); document.write( "Substitute for b, look for an integer solution for a
\n" ); document.write( "b = 3 is only single digit that works
\n" ); document.write( "a = \"19%2F8\"(3) - \"1%2F8\"
\n" ); document.write( "a = \"57%2F8\"b - \"1%2F8\"
\n" ); document.write( "a = \"56%2F8\"
\n" ); document.write( "a = 7
\n" ); document.write( " my age = 73\r
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