document.write( "Question 835861: In a certain store, there is a 0.04 probability that the scanned price in the bar code scanner will not match the advertised price. The cashier scans 874 items.\r
\n" ); document.write( "\n" ); document.write( "(a-1) What is the expected number of mismatches? (Round your answer to nearest whole number.)\r
\n" ); document.write( "\n" ); document.write( " Expected number I know it is 34.96 \r
\n" ); document.write( "\n" ); document.write( "(a-2)
\n" ); document.write( "What is the standard deviation? (Use rounded expected number for the calculation of standard deviation. Round your final answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " Standard deviation ???????????/\r
\n" ); document.write( "\n" ); document.write( "(b)
\n" ); document.write( "What is the probability of at least 29 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " Probability ?????\r
\n" ); document.write( "\n" ); document.write( "(c)
\n" ); document.write( "What is the probability of more than 43 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " Probability I know this one is .0740
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Algebra.Com's Answer #503764 by stanbon(75887)\"\" \"About 
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In a certain store, there is a 0.04 probability that the scanned price in the bar code scanner will not match the advertised price. The cashier scans 874 items.
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\n" ); document.write( "Note: Binomial problem with n = 874 and p(mismatch) = 0.04
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\n" ); document.write( "(a-1) What is the expected number of mismatches? (Round your answer to nearest whole number.)
\n" ); document.write( "mean = expected number = 874*0.04 = 34.96
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\n" ); document.write( "(a-2)
\n" ); document.write( "What is the standard deviation? (Use rounded expected number for the calculation of standard deviation. Round your final answer to 4 decimal places.)
\n" ); document.write( "Standard deviation = sqrt(npq) = sqrt(34.96*0.96) = 5.79
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\n" ); document.write( "(b)
\n" ); document.write( "What is the probability of at least 29 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)
\n" ); document.write( "Comment: I can't tell what your C-2 Table looks like.
\n" ); document.write( "The problem can be worked as a Binomial or as a Normal
\n" ); document.write( "approximation to a Binomial.
\n" ); document.write( "If the latter:
\n" ); document.write( "P(29<= x <=874) = P(28.5<= x <=874.5)
\n" ); document.write( "z(28.5) = (28.5-34.96)/5.79 = -1.12
\n" ); document.write( "z(874.5)= (874.5-34.96)/5.79 = hugh
\n" ); document.write( "Probability = p(z > -1.12) = 0.8677
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\n" ); document.write( "(c)
\n" ); document.write( "What is the probability of more than 43 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)
\n" ); document.write( "Probability = P(z > 1.2850) = 0.0994
\n" ); document.write( "Your answer was 0.0740\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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