document.write( "Question 835861: In a certain store, there is a 0.04 probability that the scanned price in the bar code scanner will not match the advertised price. The cashier scans 874 items.\r
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document.write( "(a-1) What is the expected number of mismatches? (Round your answer to nearest whole number.)\r
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document.write( " Expected number I know it is 34.96 \r
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document.write( "(a-2)
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document.write( "What is the standard deviation? (Use rounded expected number for the calculation of standard deviation. Round your final answer to 4 decimal places.)\r
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document.write( " Standard deviation ???????????/\r
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document.write( "(b)
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document.write( "What is the probability of at least 29 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)\r
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document.write( " Probability ?????\r
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document.write( "(c)
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document.write( "What is the probability of more than 43 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.)\r
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document.write( " Probability I know this one is .0740 \n" );
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Algebra.Com's Answer #503764 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In a certain store, there is a 0.04 probability that the scanned price in the bar code scanner will not match the advertised price. The cashier scans 874 items. \n" ); document.write( "------ \n" ); document.write( "Note: Binomial problem with n = 874 and p(mismatch) = 0.04 \n" ); document.write( "---------------------------------------------------------------- \n" ); document.write( "(a-1) What is the expected number of mismatches? (Round your answer to nearest whole number.) \n" ); document.write( "mean = expected number = 874*0.04 = 34.96 \n" ); document.write( "============ \n" ); document.write( "(a-2) \n" ); document.write( "What is the standard deviation? (Use rounded expected number for the calculation of standard deviation. Round your final answer to 4 decimal places.) \n" ); document.write( "Standard deviation = sqrt(npq) = sqrt(34.96*0.96) = 5.79 \n" ); document.write( "------------------ \n" ); document.write( "(b) \n" ); document.write( "What is the probability of at least 29 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.) \n" ); document.write( "Comment: I can't tell what your C-2 Table looks like. \n" ); document.write( "The problem can be worked as a Binomial or as a Normal \n" ); document.write( "approximation to a Binomial. \n" ); document.write( "If the latter: \n" ); document.write( "P(29<= x <=874) = P(28.5<= x <=874.5) \n" ); document.write( "z(28.5) = (28.5-34.96)/5.79 = -1.12 \n" ); document.write( "z(874.5)= (874.5-34.96)/5.79 = hugh \n" ); document.write( "Probability = p(z > -1.12) = 0.8677 \n" ); document.write( "---------------------------------------- \n" ); document.write( "(c) \n" ); document.write( "What is the probability of more than 43 mismatches? (Round the value of z to 2 decimals. Use Appendix C-2 to find probabilities. Round your final answer to 4 decimal places.) \n" ); document.write( "Probability = P(z > 1.2850) = 0.0994 \n" ); document.write( "Your answer was 0.0740\r \n" ); document.write( "\n" ); document.write( "------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------- \n" ); document.write( " |