document.write( "Question 835300: I have no idea how to post an image, but I was able to find an exact image on another persons question, see link below.\r
\n" ); document.write( "\n" ); document.write( "I know how to do the work, I just am unsure as to which definition (theorems) goes where, which is the only part I need help in identifying. This is what I have so far....\r
\n" ); document.write( "\n" ); document.write( "Line 1 is triangle ABC, AD bisects angle BAC and AE are ~(with equal sign)ED Reason is given\r
\n" ); document.write( "\n" ); document.write( "Line 2 is angle BAD = angle EAD with the reason AD intersects angle BAC\r
\n" ); document.write( "\n" ); document.write( "Line 3 AE = ED reason: similar sides are equal\r
\n" ); document.write( "\n" ); document.write( "Line 4 angle ADE = EAD reason property of isosceles triangles\r
\n" ); document.write( "\n" ); document.write( "Line 5 angle BAD = ADE Reason: angle BAD and angle ADE = angle EAD\r
\n" ); document.write( "\n" ); document.write( "Line 6 AB is parallel to ED Reason: lines are considered parallel\r
\n" ); document.write( "\n" ); document.write( "Line 7 angle CDE is congruent to angle CBA and CED is congruent to angle CAB Reason: angle will be congruent to each other if two parallel lines are divided by a transversal angle\r
\n" ); document.write( "\n" ); document.write( "Line 8 Angle DCE is congruent to angle BCA Reason AAA postulate\r
\n" ); document.write( "\n" ); document.write( "Line 9 1). AC/EC= BC/DC reason: conforming sides are directly in proportion to congruent triangles\r
\n" ); document.write( "\n" ); document.write( "Line 10 DC Reason subtract 1 on both sides 1).\r
\n" ); document.write( "\n" ); document.write( "Line 11 3). AE/EC = BD/DC Reason simplified line 10\r
\n" ); document.write( "\n" ); document.write( "Line 12 AE/AC = BD/BC Reason 3). divided by 2).\r
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\n" ); document.write( "\n" ); document.write( "link to image http://www.algebra.com/algebra/homework/Geometry_proofs.faq.question.630966.html
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Algebra.Com's Answer #503711 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Given: ΔABC, AD bisects ∠BAC, AE ≅ ED \r\n" );
document.write( "To prove: AE/AC = BD/BC \r\n" );
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document.write( "1  In ΔABC, AD bisects ∠BAC and AE ≅ ED ---- given \r\n" );
document.write( "2  m∠BAD = m∠EAD    ------- AD bisects ∠BAC \r\n" );
document.write( "3  ΔAED is isoceles  ------- AE ≅ ED, which is given\r\n" );
document.write( "4  m∠EAD + m∠ADE + m∠AED = 180° ------ property of all triangles\r\n" );
document.write( "5 m∠ADE = m∠EAD ------- property of isosceles ΔAED \r\n" );
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document.write( "6 m∠BAD + m∠EAD + m∠AED = 180° ------ substituting =s for =s (2 and 5) \r\n" );
document.write( "7  ∠BAC = ∠BAD + ∠EAD ------- a whole is equal to the sum of its parts.\r\n" );
document.write( "8. m∠BAC = m∠BAD + m∠EAD  ------- measure of whole equals sum of measures of parts\r\n" );
document.write( "9. m∠BAC + m∠AED = 180°  -------- substituting =s for =s (6 and 8)\r\n" );
document.write( "10. AB ∥ ED                 --------  if two interior angles on the same\r\n" );
document.write( "                                            side of a transversal cutting two\r\n" );
document.write( "                                            lines are supplementary then the\r\n" );
document.write( "                                            lines are parallel\"\r\n" );
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document.write( "11 AE/EC = BD/DC       -------- If a line parallel to a side of a triangle\r\n" );
document.write( "                                intersects the other two sides, then it \r\n" );
document.write( "                                divides those sides proportionally.\r\n" );
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document.write( "12 AE/(EC+AE) = BD/(DC+BD)   --------    Numerator addition property of a\r\n" );
document.write( "                                         proportion.\r\n" );
document.write( "13 AE/AC = BD/BC             --------     AC = EC+AE and BD = DC+BD,\r\n" );
document.write( "                                          substituting =s for =s\r\n" );
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document.write( "Edwin
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