document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835722>Question 835722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves a station and travels north at 60km/hr. Two hours later, a second train leaves on a parallel track and travels north at 100km/hr. How far from the station will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503677 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> They will never meet. Parallel lines(tracks) never meet. Good thing too. We don;t need nor want a train accident!<BR>\n" );
document.write( "When will they be the same distance from the original station?<BR>\n" );
document.write( "Three hours after the second train leaves the station.<BR>\n" );
document.write( "in the first two hours the first train traveled 2*60 =120 km<BR>\n" );
document.write( "the second train gains on the first train at 100-60=40kph<BR>\n" );
document.write( "120/40=3 hours\r<BR>\n" );
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