document.write( "Question 835614: A market gardener is preparing a report for her seed supplier. She wants to include
\n" ); document.write( "information about the mean weight of pumpkins she grows. A 95% confidence interval for
\n" ); document.write( "the mean weight when 40 pumpkins are sampled gives 4.71kg   5.93kg .
\n" ); document.write( "i) What is the mean weight of the 40 pumpkins?
\n" ); document.write( "ii) What is the margin of error in this confidence interval?
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Algebra.Com's Answer #503653 by stanbon(75887)\"\" \"About 
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A 95% confidence interval for the mean weight when 40 pumpkins are sampled gives 4.71kg 5.93kg .
\n" ); document.write( "i) What is the mean weight of the 40 pumpkins?
\n" ); document.write( "mean = (5.93+4.71)/2 = 5.32
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\n" ); document.write( "ii) What is the margin of error in this confidence interval?
\n" ); document.write( "ME = (5.93-4.71)/2 = 0.61
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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