document.write( "Question 70545: Nancy jogs and walks to school every day. She does 4km/h walking and 8km/h jogging. From home to school it is 6km and it is an 1 hour trip. Using substitution how far does Nancy jog? \n" ); document.write( "
Algebra.Com's Answer #50363 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Nancy jogs and walks to school every day. She does 4km/h walking and 8km/h jogging. From home to school it is 6km and it is an 1 hour trip. Using substitution how far does Nancy jog? \n" ); document.write( "Let the time jogged be: x \n" ); document.write( "Let the time walked be: y \n" ); document.write( "Then the total time is: x+y=1 \n" ); document.write( "Distance=rate * time \n" ); document.write( "The distance jogged is: 8x \n" ); document.write( "The distance walked is: 4y \n" ); document.write( "Then the total distance is: 8x+4y=6 \n" ); document.write( "So the system your solving is: \n" ); document.write( "x+y=1 \n" ); document.write( "8x+4y=6 \n" ); document.write( "Solve the 1st equation for y and substitute it into the second equation and solve for x. \n" ); document.write( "x+y=1 \n" ); document.write( "x-x+y=1-x \n" ); document.write( "y=1-x Substitute that in for y in the second eqaution: \n" ); document.write( "8x+4(1-x)=6 \n" ); document.write( "8x+4-4x=6 \n" ); document.write( "4x+4=6 \n" ); document.write( "4x+4-4=6-4 \n" ); document.write( "4x=2 \n" ); document.write( "4x/4=2/4 \n" ); document.write( "x=1/2 \n" ); document.write( "The distance jogged is 8x, let x=1/2, and the distance jogged is: 8(1/2)=4km \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |