document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835556>Question 835556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side of a triangle is three times the shortest side.The third side is 7 feet more than the shortest side. The perimeter is 62 feet. Find all three sides.<BR>\n" );
document.write( "        Thanks Michael </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503600 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the shortest side, so that the other two sides are 3x and x+7. Then\r<BR>\n" );
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document.write( "x + 3x + (x+7) = 62<BR>\n" );
document.write( "x = 11\r<BR>\n" );
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document.write( "The sides are 11, 33, 18. This is a bad problem, since 11, 18, 33 cannot be the sides of a triangle (11 + 18 < 33). </SPAN>\n" );
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