document.write( "Question 835522: A car was bought at the beginning of 1994. During the first year it depreciated in value by 23% and then by 9% each subsequent year. If it's original price was Ł9,000, what was its value at the end of 1997, to the nearest pound? \n" ); document.write( "

Algebra.Com's Answer #503593 by josmiceli(19441) $\"\"$ $\"About$

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For now, say the original price was $\"+p+\"$
\n" ); document.write( "After the 1st year, it's value is:
\n" ); document.write( " $\"+p+-+.23p+=+.77p+\"$
\n" ); document.write( "After the 2nd year, it's value is:
\n" ); document.write( " $\"+.77p+-+.09%2A.77p+=+.77p+-+.0693p+\"$
\n" ); document.write( " $\"+.77p+-+.0693p+=+.7007p+\"$
\n" ); document.write( "After the 3rd year, it's value is:
\n" ); document.write( " $\"+.7007p+-+.09%2A.7007p+=+.7007p+-+.0631p+\"$
\n" ); document.write( " $\"+.7007p+-+.0631p+=+.6376p+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( " $\"+p+=+9000+\"$
\n" ); document.write( " $\"+.6376p+=+.6376%2A9000+\"$
\n" ); document.write( " $\"+.6376p+=+5738.4+\"$
\n" ); document.write( "To the nearest pound, it's value is 5,738
\n" ); document.write( "at the end of 1997\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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