document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835223>Question 835223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me find csc0 if cot0 = the - square root of 3 and cos 0 <0\r<BR>\n" );
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document.write( "i tried to do cot^20 = (- square root of 3)^2<BR>\n" );
document.write( "cot2x= -3<BR>\n" );
document.write( "1/tan = -3<BR>\n" );
document.write( "1(1/1-sec2x) = (-3)1<BR>\n" );
document.write( "1-sec^2x = -3<BR>\n" );
document.write( "1-1/cosx = -3<BR>\n" );
document.write( "-1/cosx = -2<BR>\n" );
document.write( "1(1/cosx) = (-2)1<BR>\n" );
document.write( "cosx= -2\r<BR>\n" );
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document.write( "But I ended up confusing myself more than getting the answer right. Please help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503444 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find csc0 if cot0 = -sqrt(3) and cos 0 < 0 <BR>\n" );
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document.write( "Note: cot and cos are both negative in QII where x < 0 and y > 0<BR>\n" );
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document.write( "Since cot = x/y, x = -sqrt(3) and y = 1<BR>\n" );
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document.write( "Then r = sqrt[(sqrt(3))^2+1^2] = sqrt[3+1] = 2<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "csc(t) = r/y = 2/1 = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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