document.write( "Question 826318: larry has a collection of nickels, dimes, and quarters totaling more than $7.50. The number of nickels is 3 times the number of dimes and the number of quarters is 4 times the number of dimes. find the least possible number of dimes in the collection. \n" ); document.write( "

Algebra.Com's Answer #503425 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
larry has a collection of nickels, dimes, and quarters totaling more than $7.50.

$0.05n + $0.10d + $0.25q > $7.50\r\n" );
document.write( "\r\n" );
document.write( "Clear of decimals:\r\n" );
document.write( "\r\n" );
document.write( "          5n + 10d + 25q > 750\r\n" );
document.write( "\r\n" );
document.write( "Divide through by 5\r\n" );
document.write( "\r\n" );
document.write( "             n + 2d + 5q > 150

The number of nickels is 3 times the number of dimes

n = 3d

and the number of quarters is 4 times the number of dimes.

q = 4d\r\n" );
document.write( "\r\n" );
document.write( "Substituting:\r\n" );
document.write( "\r\n" );
document.write( "             n + 2d + 5q > 150\r\n" );
document.write( "         3d + 2d + 5(4d) > 150\r\n" );
document.write( "           3d + 2d + 20d > 150\r\n" );
document.write( "                     25d > 150\r\n" );
document.write( "                       d > 6

find the least possible number of dimes in the collection.

So the least possible number of dimes greater than 6 is 7.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );