document.write( "Question 835204: What are the steps in solving this? | 2v - 1 | less than or equal to 9. Note: I don't know how to do the symbol for less than or equal to on my ipad. \n" ); document.write( "
Algebra.Com's Answer #503406 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+abs%28+2v+-+1+%29+%3C=+9+\"
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\n" ); document.write( "Anything that you take the absolute value of will
\n" ); document.write( "be \"+0+\" or a positive number, so
\n" ); document.write( "you know that the range of the left side
\n" ); document.write( "is \"+0+\" to \"9\" inclusive
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\n" ); document.write( "\"+0+%3C=+abs%28+2v-1+%29+%3C=+9+\"
\n" ); document.write( "I can say:
\n" ); document.write( "(1) \"+0+%3E=+2v+-+1+%3E=+-9+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+0+%3C=+2v+-+1+%3C=+9+\"
\n" ); document.write( "==================
\n" ); document.write( "(1) \"+2v+-+1+%3C=+0+\"
\n" ); document.write( "(1) \"+2v+%3C=+1+\"
\n" ); document.write( "(1) \"+v+%3C=+1%2F2+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+2v+-+1+%3E=+-9+\"
\n" ); document.write( "(1) \"+2v+%3E=+-8+\"
\n" ); document.write( "(1) \"+v+%3E=+-4+\"
\n" ); document.write( "-------------------
\n" ); document.write( "(2) \"+2v+-+1+%3E=+0+\"
\n" ); document.write( "(2) \"+2v+%3E=1+\"
\n" ); document.write( "(2) \"+v+%3E=+1%2F2+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+2v+-+1+%3C=+9+\"
\n" ); document.write( "(2) \"+2v+%3C=+10+\"
\n" ); document.write( "(2) \"+v+%3C=+5+\"
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\n" ); document.write( "Rearranging the conditions:
\n" ); document.write( "(1) \"+v+%3C=+1%2F2+\"
\n" ); document.write( "(2) \"+v+%3C=+5+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+v+%3E=+-4+\"
\n" ); document.write( "(2) \"+v+%3E=+1%2F2+\"
\n" ); document.write( "------------------
\n" ); document.write( "The controlling conditions are:
\n" ); document.write( "\"+-4+%3C=+v+%3C=+5+\"\r
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