document.write( "Question 835040: a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
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Algebra.Com's Answer #503312 by stanbon(75887) $\"\"$ $\"About$

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a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
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\n" ); document.write( "Equations:
\n" ); document.write( "s = d + 3
\n" ); document.write( "f+1 = 6d
\n" ); document.write( "f+10 = (s+10) + (d+10) + 14
\n" ); document.write( "----
\n" ); document.write( "f+10 = (d+13) + d+10 + 14
\n" ); document.write( "f = 2d +13+14
\n" ); document.write( "f = 2d + 27
\n" ); document.write( "----
\n" ); document.write( "f+1 = 2d + 28
\n" ); document.write( "6d = 2d + 28
\n" ); document.write( "4d = 28
\n" ); document.write( "daughter = 7 yrs (now)
\n" ); document.write( "----
\n" ); document.write( "son = d+3 = 10 yrs (now)
\n" ); document.write( "father = 6d-1 = 41 yrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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