document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835019>Question 835019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan(a+B) if csc=13/5, tanB= 4/3, and both angles are located in quadrant I.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503300 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan(a+B) if csc(a)=13/5, tanB= 4/3, and both angles are located in quadrant I. <BR>\n" );
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document.write( "tan(a+B) = [tan(a)+tan(B)]/[1-tan(a)tan(B)]<BR>\n" );
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document.write( "csc = r/y, so r = 13 and y = 5<BR>\n" );
document.write( "Then x = sqrt[13^2-5^2] = 12<BR>\n" );
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document.write( "Therefore: tan(a) = y/x = 5/12<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "tan(a+B) = [(5/12)+(4/3)]/[1-(5/12)(4/3)] = (21/12)/(5/9) = 35/36<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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