document.write( "Question 70514: Need help with solving this, please? Thanks!\r
\n" ); document.write( "\n" ); document.write( "Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs?
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Algebra.Com's Answer #50328 by funmath(2933)\"\" \"About 
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Need help with solving this, please? Thanks!\r
\n" ); document.write( "\n" ); document.write( "Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs?
\n" ); document.write( "The formula for interest compounded continously is: \"highlight%28A=Pe%5E%28rt%29%29\", where A=amount, t=years, and r=interest rate.
\n" ); document.write( "In your case P=2000; r=6/100=.06; and t1=1 and t2=2
\n" ); document.write( "After 1 year:
\n" ); document.write( "\"A=2000e%5E%28%28.06%29%281%29%29\"
\n" ); document.write( "\"A=2000e%5E.06\" You need a scientific calculator for this. If your calculator doesn't have e, use 2.718281828 for e.
\n" ); document.write( "A=$2123.67
\n" ); document.write( "After 2 years:
\n" ); document.write( "\"A=2000e%5E%28%28.06%29%282%29%29\"
\n" ); document.write( "\"A=2000e%5E.12\"
\n" ); document.write( "A=$2254.99
\n" ); document.write( "Happy Calculating!!!
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