document.write( "Question 70514: Need help with solving this, please? Thanks!\r
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document.write( "Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs? \n" );
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Algebra.Com's Answer #50328 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Need help with solving this, please? Thanks!\r \n" ); document.write( "\n" ); document.write( "Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs? \n" ); document.write( "The formula for interest compounded continously is: \n" ); document.write( "In your case P=2000; r=6/100=.06; and t1=1 and t2=2 \n" ); document.write( "After 1 year: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "A=$2123.67 \n" ); document.write( "After 2 years: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "A=$2254.99 \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |