document.write( "Question 70529: Please help me solve: 1 / 3 ^3 minus [ ( 2 / 3 + 1 / 2 ) divided by 2 / 3 ]\r
\n" ); document.write( "\n" ); document.write( "1 / 3 cubed = 1 / 27
\n" ); document.write( "2 / 3 + 1 / 2 = 4/6 + 3/6 = 7/6
\n" ); document.write( "7/6 divded by 2/3 = 7/6 * 3/2 = 21/12 = 7/4\r
\n" ); document.write( "\n" ); document.write( "1/27 - 7/4 = 4/108 - 189/108 = - 185/108 ?????? = 1 and 77/108 ?????
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Algebra.Com's Answer #50324 by funmath(2933)\"\" \"About 
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Please help me solve: 1 / 3 ^3 minus [ ( 2 / 3 + 1 / 2 ) divided by 2 / 3 ]\r
\n" ); document.write( "\n" ); document.write( "1 / 3 cubed = 1 / 27 (RIGHT!!!!!:-)
\n" ); document.write( "2 / 3 + 1 / 2 = 4/6 + 3/6 = 7/6 (RIGHT!!!!!!!!!:-)
\n" ); document.write( "7/6 divded by 2/3 = 7/6 * 3/2 = 21/12 = 7/4 (RIGHT!!!!!!:-)\r
\n" ); document.write( "\n" ); document.write( "1/27 - 7/4 = 4/108 - 189/108 = - 185/108 (RIGHT!!!!!:-) = 1 and 77/108 ?????
\n" ); document.write( "The last thing you did was right, except you forgot the negative -1 and 77/108.
\n" ); document.write( "You did a great job---keep it up!!!!
\n" ); document.write( "Happy Calculating!!!!
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