document.write( "Question 70529: Please help me solve: 1 / 3 ^3 minus [ ( 2 / 3 + 1 / 2 ) divided by 2 / 3 ]\r
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document.write( "1 / 3 cubed = 1 / 27
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document.write( "2 / 3 + 1 / 2 = 4/6 + 3/6 = 7/6
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document.write( "7/6 divded by 2/3 = 7/6 * 3/2 = 21/12 = 7/4\r
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document.write( "1/27 - 7/4 = 4/108 - 189/108 = - 185/108 ?????? = 1 and 77/108 ????? \n" );
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Algebra.Com's Answer #50324 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Please help me solve: 1 / 3 ^3 minus [ ( 2 / 3 + 1 / 2 ) divided by 2 / 3 ]\r \n" ); document.write( "\n" ); document.write( "1 / 3 cubed = 1 / 27 (RIGHT!!!!!:-) \n" ); document.write( "2 / 3 + 1 / 2 = 4/6 + 3/6 = 7/6 (RIGHT!!!!!!!!!:-) \n" ); document.write( "7/6 divded by 2/3 = 7/6 * 3/2 = 21/12 = 7/4 (RIGHT!!!!!!:-)\r \n" ); document.write( "\n" ); document.write( "1/27 - 7/4 = 4/108 - 189/108 = - 185/108 (RIGHT!!!!!:-) = 1 and 77/108 ????? \n" ); document.write( "The last thing you did was right, except you forgot the negative -1 and 77/108. \n" ); document.write( "You did a great job---keep it up!!!! \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |