document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834555>Question 834555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I'm really confused with this question...\r<BR>\n" );
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document.write( "A shopkeeper mixed a herb worth $2.50 a kilogram with another herb worth $3.50 a kilogram. He sold 20 kilograms of the mixture at $2.80 per kilogram. Find the weights of the two different herbs he mixed together. \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503214 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A shopkeeper mixed a herb worth $2.50 a kilogram with another herb worth $3.50 a kilogram.<BR>\n" );
document.write( " He sold 20 kilograms of the mixture at $2.80 per kilogram.\<BR>\n" );
document.write( " Find the weights of the two different herbs he mixed together.<BR>\n" );
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document.write( "Let a = amt of $2.50 herbs<BR>\n" );
document.write( "Let b = amt of $3.50 herbs<BR>\n" );
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document.write( "Two equations<BR>\n" );
document.write( "the weight equation<BR>\n" );
document.write( "a + b = 20<BR>\n" );
document.write( "or<BR>\n" );
document.write( "a = (20-b); use this form for substitution<BR>\n" );
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document.write( "the $ amt equation<BR>\n" );
document.write( "2.50a + 3.50b = 2.80(20)<BR>\n" );
document.write( "2.50a + 3.50b = 56<BR>\n" );
document.write( "Replace a with (20-b)<BR>\n" );
document.write( "2.5(20-b) + 3.5b = 56<BR>\n" );
document.write( "50 - 2.5b + 3.5b = 56<BR>\n" );
document.write( "-2.5b + 3.5b = 56 - 50<BR>\n" );
document.write( "b = 6 kg of the 3.50 herb<BR>\n" );
document.write( "then<BR>\n" );
document.write( "a =  20 - 6<BR>\n" );
document.write( "a = 14 kg of the 2.50 herb<BR>\n" );
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document.write( "Check the solutions in the $ equation<BR>\n" );
document.write( "2.5(14) + 3.5(6) = 2.8(20)<BR>\n" );
document.write( "35 + 21 = 56<BR>\n" );
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document.write( "Did we manage to \"unconfuse\" you here? </SPAN>\n" );
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