document.write( "Question 834741: if cscθ=4 and θ is in quadrant II, find the exact value of sin2θ \n" ); document.write( "
Algebra.Com's Answer #503213 by stanbon(75887)\"\" \"About 
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if cscθ=4 and θ is in quadrant II, find the exact value of sin2θ
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\n" ); document.write( "With theta in QII, x is negative and y is positive.
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\n" ); document.write( "Since csc = r/y, r = 4 and y = 1
\n" ); document.write( "Therefore -x = -sqrt[4^2-1^2] = -sqrt(15)
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\n" ); document.write( "Your Problem::
\n" ); document.write( "sin(2t) = 2*sin(t)cos(t) = 2(y/r)(x/r) = 2(1/4)(-sqrt(15)/4) = -sqrt(15)/8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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