document.write( "Question 834741: if cscθ=4 and θ is in quadrant II, find the exact value of sin2θ \n" ); document.write( "
Algebra.Com's Answer #503213 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! if cscθ=4 and θ is in quadrant II, find the exact value of sin2θ \n" ); document.write( "----------------------------- \n" ); document.write( "With theta in QII, x is negative and y is positive. \n" ); document.write( "----------------------------- \n" ); document.write( "Since csc = r/y, r = 4 and y = 1 \n" ); document.write( "Therefore -x = -sqrt[4^2-1^2] = -sqrt(15) \n" ); document.write( "------- \n" ); document.write( "Your Problem:: \n" ); document.write( "sin(2t) = 2*sin(t)cos(t) = 2(y/r)(x/r) = 2(1/4)(-sqrt(15)/4) = -sqrt(15)/8 \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============================== \n" ); document.write( " |