document.write( "Question 834556: I cannot comprehend this question :
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document.write( " 3x+1<7 or 7 is less than or equals to 2x -9 (yes this is ONE problem) *i also would like to apologize it would be than or equals to*
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document.write( "I did try and I ended up with x<2.67 and the second would be -1 is less than or equals to x \n" );
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Algebra.Com's Answer #503208 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! 3x + 1 < 7 <= 2x + 9 \n" ); document.write( "subtract 1 \n" ); document.write( "3x < 6 <= 2x + 8 \n" ); document.write( "Two equations \n" ); document.write( "3x < 6 \n" ); document.write( "x < 6/3 \n" ); document.write( "x < 2 \n" ); document.write( "and rewrite the 2nd one reversing the inequality sign \n" ); document.write( "2x + 8 >= 6 \n" ); document.write( "2x >= 6 - 8 \n" ); document.write( "2x >= -2 \n" ); document.write( "x >= -1 \n" ); document.write( " \n" ); document.write( " |