document.write( "Question 834556: I cannot comprehend this question :
\n" ); document.write( " 3x+1<7 or 7 is less than or equals to 2x -9 (yes this is ONE problem) *i also would like to apologize it would be than or equals to*
\n" ); document.write( "I did try and I ended up with x<2.67 and the second would be -1 is less than or equals to x
\n" ); document.write( "

Algebra.Com's Answer #503208 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
3x + 1 < 7 <= 2x + 9
\n" ); document.write( "subtract 1
\n" ); document.write( "3x < 6 <= 2x + 8
\n" ); document.write( "Two equations
\n" ); document.write( "3x < 6
\n" ); document.write( "x < 6/3
\n" ); document.write( "x < 2
\n" ); document.write( "and rewrite the 2nd one reversing the inequality sign
\n" ); document.write( "2x + 8 >= 6
\n" ); document.write( "2x >= 6 - 8
\n" ); document.write( "2x >= -2
\n" ); document.write( "x >= -1
\n" ); document.write( "
\n" ); document.write( "
\n" );