document.write( "Question 834528: with a current, you can canoe 64 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 hours. Find your rate in still water \n" ); document.write( "
Algebra.Com's Answer #503144 by ankor@dixie-net.com(22740)\"\" \"About 
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with a current, you can canoe 64 miles in 4 hours.
\n" ); document.write( " Against the same current, you can canoe only 3/4 of this distance in 6 hours.
\n" ); document.write( " Find your rate in still water.
\n" ); document.write( ":
\n" ); document.write( "Find the distance against the current. \"3%2F4\"*64 = 48 miles
\n" ); document.write( ":
\n" ); document.write( "Let s = canoe speed in still water
\n" ); document.write( "let c = rate of the current
\n" ); document.write( "then
\n" ); document.write( "(s+c) = effective speed with the current
\n" ); document.write( "and
\n" ); document.write( "(s-c) = effective speed against
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation for each way. dist = time * speed
\n" ); document.write( "4(s+c) = 64
\n" ); document.write( "6(s-c) = 48
\n" ); document.write( "Simplify, divide the 1st equation by 4, the 2nd equation by 6, results
\n" ); document.write( "s + c = 16
\n" ); document.write( "s - c = 8
\n" ); document.write( "--------------Addition eliminates c find s
\n" ); document.write( "2s + 0 = 24
\n" ); document.write( "s = 24/2
\n" ); document.write( "s = 12 mph is the speed in still water
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You can confirm this yourself, find the rate of the current.
\n" ); document.write( "Check it in both equations \n" ); document.write( "
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