document.write( "Question 834632: A bus leaves LA traveling at 50 mi/hr. An hour later a car traveling on the same road leaves at 70 mi/hr to try to overtake the bus. how far from LA does the car overtake the bus? \n" ); document.write( "
Algebra.Com's Answer #503110 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Notice the slow vehicle leaves first and travels for more time. In this example, the time difference is 1 hour. The slow vehicle travels for t+1 hours of time. The faster but later-starting vehicle travels for some t hours of time. t is an unknown variable. When that information is straight, then continue....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "READY?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = time for the car to meet the same distance as the traveling bus \n" ); document.write( "d = the distance from LA that car and distance match\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In case a table would help,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "____________________speed_____________time______________distance \n" ); document.write( "Bus_________________50________________t+1_______________d \n" ); document.write( "Car_________________70________________t_________________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Basic equation for uniform rates for travel, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "... Further process is not continued here (yet), but you try to solve the example exercise yourself, from what has been presented so far. Can you continue and finish? \n" ); document.write( " |