document.write( "Question 834620: the dimensions of a rectangle are such that it's length is 9 inches more than it's width. If the length were doubled and its width is decreased by 4 in, the area would be increased by 138in^2. What are the length and width of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "I think the set up is this but not sure:
\n" ); document.write( " (x+9)(x)=2(x+9)(x-4)+138
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Algebra.Com's Answer #503099 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
(x+9)(x)=2(x+9)(x-4)+138
\n" ); document.write( "should be
\n" ); document.write( "(x+9)(x)+138=2(x+9)(x-4)
\n" ); document.write( "x = 14
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\n" ); document.write( "23*14+138=46*10
\n" ); document.write( "322+138=460
\n" ); document.write( "ok
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