document.write( "Question 834596: You have 4L of an 90% aqueous solution of hydrochloric acid. You want 1L of a 25% solution. How much of the stock solution do you need to use? \n" ); document.write( "
Algebra.Com's Answer #503092 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
point of view of acid
\n" ); document.write( ".9x=.25(x+y),
\n" ); document.write( "x+y=1
\n" ); document.write( "x=0.277778 acid , y=0.722222 water
\n" ); document.write( "check
\n" ); document.write( ".9(0.277778)=.25(1),
\n" ); document.write( "ok\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "point of view of water
\n" ); document.write( ".1(x)+y=.75*(x+y),
\n" ); document.write( "x+y=1
\n" ); document.write( "x=0.277778 acid , y=0.722222 water
\n" ); document.write( "check
\n" ); document.write( ".1(0.277778)+0.722222=.75*(1)
\n" ); document.write( "ok
\n" ); document.write( "
\n" );