document.write( "Question 834596: You have 4L of an 90% aqueous solution of hydrochloric acid. You want 1L of a 25% solution. How much of the stock solution do you need to use? \n" ); document.write( "
Algebra.Com's Answer #503092 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! point of view of acid \n" ); document.write( ".9x=.25(x+y), \n" ); document.write( "x+y=1 \n" ); document.write( "x=0.277778 acid , y=0.722222 water \n" ); document.write( "check \n" ); document.write( ".9(0.277778)=.25(1), \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "point of view of water \n" ); document.write( ".1(x)+y=.75*(x+y), \n" ); document.write( "x+y=1 \n" ); document.write( "x=0.277778 acid , y=0.722222 water \n" ); document.write( "check \n" ); document.write( ".1(0.277778)+0.722222=.75*(1) \n" ); document.write( "ok \n" ); document.write( " |