document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834573>Question 834573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of an object tossed upward with an initial velocity of 104 feet per second is given bythe formula h = 16t^2 + 104t, where h is the height in feet and t is the time in seconds. What is the time required for the object to return to its point of departure?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #503062 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=503062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given:<BR>\n" );
document.write( "h = -16t^2 + 104t<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The \"initial\" point of departure is when 'h' is zero.  So, set h to zero and solve for t:<BR>\n" );
document.write( "0 = -16t^2 + 104t<BR>\n" );
document.write( "0 = 4t(-4t + 26)<BR>\n" );
document.write( "t = {0,13/2}<BR>\n" );
document.write( "answer:<BR>\n" );
document.write( "t = 13/2 seconds<BR>\n" );
document.write( "or<BR>\n" );
document.write( "t = 6.5 seconds </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );