document.write( "Question 834522: Hello! I need help on solving x for this equation:\r
\n" ); document.write( "\n" ); document.write( "log(base 2)x = log(base x)e\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #503048 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
solving x for this equation:
\n" ); document.write( "log(base 2)x = log(base x)e
\n" ); document.write( "convert to base(2)
\n" ); document.write( "\"log%282%2C%28x%29%29=log%282%2C%28e%29%29%2Flog%282%2C%28x%29%29\"
\n" ); document.write( "\"%28log%282%2C%28x%29%29%29%5E2=log%282%2C%28e%29%29\"
\n" ); document.write( "\"%28log%282%2C%28x%29%29%29%5E2=log%282%2C%28e%29%29\"
\n" ); document.write( "\"log%282%2C%28x%29%29=sqrt%28log%282%2C%28e%29%29%29\"
\n" ); document.write( "note:reject negative root
\n" ); document.write( "\"sqrt%28log%282%2C%28e%29%29%29=1.2011\"
\n" ); document.write( "\"log%282%2C%28x%29%29=1.2011\"
\n" ); document.write( "x=2^1.2011≈2.2991
\n" ); document.write( "check:
\n" ); document.write( "log(base 2)x≈1.2011
\n" ); document.write( "log(base x)e≈1.2011
\n" ); document.write( "
\n" );