document.write( "Question 834063: Find the vertices and foci of the hyperbola.
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document.write( "16x2 − y2 − 64x − 4y + 44 = 0 \n" );
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Algebra.Com's Answer #503045 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertices and foci of the hyperbola. \n" ); document.write( "16x2 − y2 − 64x − 4y + 44 = 0 \n" ); document.write( "*** \n" ); document.write( "16x^2-64x-y^2+4y=-44 \n" ); document.write( "hyperbola has a horizontal transverse axis. \n" ); document.write( "Its standard form of equation: \n" ); document.write( "complete the square \n" ); document.write( "16(x^2-4x+4)-(y^2-4y+4)=-44+64-4 \n" ); document.write( "16(x-2)^2-(y-2)^2=16 \n" ); document.write( "equation: \n" ); document.write( "center: (2,2) \n" ); document.write( "a^2=1 \n" ); document.write( "a=1 \n" ); document.write( "vertices: (2±a,2)=(2±1,2)=(1,2) and (3,2) \n" ); document.write( "b^2=16 \n" ); document.write( "b=4 \n" ); document.write( "c^2=a^2+b^2=1+16=17 \n" ); document.write( "c=√17≈4.1 \n" ); document.write( "foci:(2±c,2)=(2±4.1,2)=(-2.1,2) and (6.1,2)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |