document.write( "Question 834353: A right circular cone has a base radius of 2x-5 and a height of 3x. The cone has a volume of 125pi cubic units. Find the possible value(s) of x. \n" ); document.write( "
Algebra.Com's Answer #503028 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A right circular cone has a base radius of 2x-5 and a height of 3x. \n" ); document.write( " The cone has a volume of 125pi cubic units. \n" ); document.write( " Find the possible value(s) of x. \n" ); document.write( ": \n" ); document.write( "The Vol of cone: \n" ); document.write( "so we have \n" ); document.write( " \n" ); document.write( "Get rid of the fraction multiply both sides by 3 \n" ); document.write( " \n" ); document.write( "divide both sides by pi \n" ); document.write( " \n" ); document.write( "Foil \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Group factor \n" ); document.write( " \n" ); document.write( "Factor (x-5) \n" ); document.write( "(x-5)(12x^2+75) = 0 \n" ); document.write( "one positive solution \n" ); document.write( "x = 5 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "See if this works out \n" ); document.write( "r = 2(5) - 5 \n" ); document.write( "r = 5 \n" ); document.write( "h = 3*5 = 15 \n" ); document.write( "Use a calc \n" ); document.write( " \n" ); document.write( "392.7 = 392.7 \n" ); document.write( " \n" ); document.write( " |