document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70412>Question 70412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please explain...instructions.\r<BR>\n" );
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document.write( "Tickets for a play at the community theater cost $20 for an adult and $8 for a child...if 220 tickets were sold and the total receipts were $3200, how many of each type of ticket were sold.\r<BR>\n" );
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document.write( "20x + 8y = 3200 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50302 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK You can work this problem using two unknowns:\r<BR>\n" );
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document.write( "Let x=number of adult tickets sold<BR>\n" );
document.write( "And y=number of child tickets sold\r<BR>\n" );
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document.write( "Then as you say:\r<BR>\n" );
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document.write( "20x+8y=3200--------------Equation 1.\r<BR>\n" );
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document.write( "The other equation is:\r<BR>\n" );
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document.write( "x+y=220-----------------Equation 2.\r<BR>\n" );
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document.write( "(1)         20x+8y=3200<BR>\n" );
document.write( "(2)           x+y=220\r<BR>\n" );
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document.write( "multiply equation (2) by 8\r<BR>\n" );
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document.write( "(1)         20x+8y=3200<BR>\n" );
document.write( "(2a)         8x+8y=1760\r<BR>\n" );
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document.write( "subtract (2) from (1)\r<BR>\n" );
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document.write( "12x=1440  divide both sides by 12\r<BR>\n" );
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document.write( "x=120-----------------------number of adult tickets sold\r<BR>\n" );
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document.write( "Now substitute x=120 into (2)<BR>\n" );
document.write( "120+y=220  subtract 120 from both sides\r<BR>\n" );
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document.write( "y=100-----------------------number of child tickets sold\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "120*20+100*8=3200<BR>\n" );
document.write( "2400+800=3200<BR>\n" );
document.write( "3200=3200\r<BR>\n" );
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document.write( "You can also work this problem using one unknown:\r<BR>\n" );
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document.write( "Let x=number of adult tickets sold\r<BR>\n" );
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document.write( "Then 220-x=number of child tickets sold\r<BR>\n" );
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document.write( "Now we are told that cost of adult tickets sold plus cost of child tickets sold equals $3200.  So our equation to solve is:\r<BR>\n" );
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document.write( "20x+8(220-x)=3200  get rid of parens<BR>\n" );
document.write( "20x+1760-8x=3200 subtract 1760 from both sides\r<BR>\n" );
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document.write( "12x=1440  divide both sides by 12\r<BR>\n" );
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document.write( "x=120--------------------------------number of adult tickets sold<BR>\n" );
document.write( "22-x=220-120=100----------------------number of child tickets sold\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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