document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834454>Question 834454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a particular flight, the fastest plane requires 3 hrs and the slower one 3 hrs and 36 minutes.  The fastest plane flies at a ground speed 75 miles per hour faster than another.  What is the distance of the flight? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502999 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let F = fastest, and S = slowest.<BR>\n" );
document.write( "They're covering the same distance.<BR>\n" );
document.write( "F is 1.2 times as fast as S (3.6/3 -- the .6 is 36/60 [minutes])<BR>\n" );
document.write( "If F = S + 75 and F = 1.2S, we can substitute the value of F<BR>\n" );
document.write( "1.2S = S + 75<BR>\n" );
document.write( "Subtract S from each side<BR>\n" );
document.write( ".2S = 75<BR>\n" );
document.write( "Multiply each side by 5 (to get a whole S)<BR>\n" );
document.write( "S = 375; therefore F = 450 (The fastest plane flies at a ground speed 75 miles per hour faster than another.)<BR>\n" );
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document.write( "If F flies at 450mph for 3 hours, then the distance is 1350<BR>\n" );
document.write( "S flies for 3.6 hours at 375 (3.6 * 375) = 1350<BR>\n" );
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document.write( "Sort of a convoluted problem!  I'm sure there are many ways to solve it.  This is just one. </SPAN>\n" );
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