document.write( "Question 834443: 10 years from now, Lisa will be 3 times the age she was 6 years ago.What is her present age? \n" ); document.write( "
Algebra.Com's Answer #502997 by jgr45(31)\"\" \"About 
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Let x = present age
\n" ); document.write( "age 6 years ago = x - 6
\n" ); document.write( "age 10 years hence = x + 10\r
\n" ); document.write( "\n" ); document.write( "Ten years from now her age will be triple what it was six years ago:
\n" ); document.write( "x + 10 = 3(x - 6)\r
\n" ); document.write( "\n" ); document.write( "3x - 18 = x + 10
\n" ); document.write( "3x = x + 28
\n" ); document.write( "2x = 28
\n" ); document.write( "x = 14; She is age 14 at present.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "14 + 10 =? 3 (14-6)
\n" ); document.write( "24 =? 3(8)
\n" ); document.write( "24 = 24 \"check\"
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