document.write( "Question 834443: 10 years from now, Lisa will be 3 times the age she was 6 years ago.What is her present age? \n" ); document.write( "
Algebra.Com's Answer #502997 by jgr45(31)![]() ![]() You can put this solution on YOUR website! Let x = present age \n" ); document.write( "age 6 years ago = x - 6 \n" ); document.write( "age 10 years hence = x + 10\r \n" ); document.write( "\n" ); document.write( "Ten years from now her age will be triple what it was six years ago: \n" ); document.write( "x + 10 = 3(x - 6)\r \n" ); document.write( "\n" ); document.write( "3x - 18 = x + 10 \n" ); document.write( "3x = x + 28 \n" ); document.write( "2x = 28 \n" ); document.write( "x = 14; She is age 14 at present.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "14 + 10 =? 3 (14-6) \n" ); document.write( "24 =? 3(8) \n" ); document.write( "24 = 24 |