document.write( "Question 834443: 10 years from now, Lisa will be 3 times the age she was 6 years ago.What is her present age? \n" ); document.write( "
Algebra.Com's Answer #502994 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! L + 10 = 3 (L - 6) \n" ); document.write( "Distribute the L \n" ); document.write( "L+10 = 3L - 18 \n" ); document.write( "Add 18 to each side \n" ); document.write( "L + 28 = 3L \n" ); document.write( "Subtract L from each side \n" ); document.write( "28 = 2L \n" ); document.write( "Divide by 2 \n" ); document.write( "14 = L \n" ); document.write( ". \n" ); document.write( "Let's make sure it works. \n" ); document.write( "10 years from now, Lisa will be (14+10=24) - is that 3 times the age she was 6 years ago? 6 years ago, she was 14-6=8. 8*3 = 24 \n" ); document.write( "Success! \n" ); document.write( " |