document.write( "Question 834443: 10 years from now, Lisa will be 3 times the age she was 6 years ago.What is her present age? \n" ); document.write( "
Algebra.Com's Answer #502994 by JulietG(1812)\"\" \"About 
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L + 10 = 3 (L - 6)
\n" ); document.write( "Distribute the L
\n" ); document.write( "L+10 = 3L - 18
\n" ); document.write( "Add 18 to each side
\n" ); document.write( "L + 28 = 3L
\n" ); document.write( "Subtract L from each side
\n" ); document.write( "28 = 2L
\n" ); document.write( "Divide by 2
\n" ); document.write( "14 = L
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\n" ); document.write( "Let's make sure it works.
\n" ); document.write( "10 years from now, Lisa will be (14+10=24) - is that 3 times the age she was 6 years ago? 6 years ago, she was 14-6=8. 8*3 = 24
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