document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834390>Question 834390</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A canoeist can paddle 20.0 mi down a certain river and back in 8.0 h (40.0 mi<BR>\n" );
document.write( "round trip). She can also paddle 5.0 mi down river in the same time as she<BR>\n" );
document.write( "paddles 3.0 mi up river. Find her rate in still water, and &#64257;nd the rate of the<BR>\n" );
document.write( "current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502970 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r*t=d<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "a+b=8,<BR>\n" );
document.write( "a*(x+c))+b*(x-c)=40,<BR>\n" );
document.write( "a*(x+c))=b*(x-c),<BR>\n" );
document.write( "5/(c+x)=3/(x-c)<BR>\n" );
document.write( "a = 3,   b = 5,   c = 4/3,   x = 16/3<BR>\n" );
document.write( "speed in still water 16/3<BR>\n" );
document.write( "current speed 4/3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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