document.write( "Question 834239: I am working on Factoring with the Box in unit 7 but lets say i have a problem like this x squared - 2x- 6x + 16. How would i solve it? \n" ); document.write( "
Algebra.Com's Answer #502940 by Edwin McCravy(20077)\"\" \"About 
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document.write( "x²-2x-6x+16\r\n" );
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document.write( "Combine the two middle terms:\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "Make sure the trinomial is in descending order\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "1. Make a 4-square box\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "2. Put the first term in the upper left box:\r\n" );
document.write( "   Put the last term in the lower right box:\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "3. Multiply their coefficients (ignoring signs): (1)(16) = 16\r\n" );
document.write( "   Factor the product into all factor pairs:\r\n" );
document.write( "                 16\r\n" );
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document.write( "               16  1\r\n" );
document.write( "                8  2\r\n" );
document.write( "                4  4\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "4. Add each set of factor pairs, since last term is positive.\r\n" );
document.write( "   (We would subtract them if the last term were negative)\r\n" );
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document.write( "                 16\r\n" );
document.write( "                 /\\r\n" );
document.write( "               16  1  16+1=17\r\n" );
document.write( "                8  2   8+2=10\r\n" );
document.write( "                4  4   4+4=8\r\n" );
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document.write( "x²-8x+16 \r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "5. Match the absolute value of the middle term coefficient with \r\n" );
document.write( "   the same term\r\n" );
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document.write( "That's 8.\r\n" );
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document.write( "                 16\r\n" );
document.write( "                 /\\r\n" );
document.write( "               16  1  16+1=17\r\n" );
document.write( "                8  2   8+2=10\r\n" );
document.write( "                4  4   4+4=8\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "6. Put one of the factors in the upper right box and put an x after it,\r\n" );
document.write( "   (or whatever the variable letter happens to be)\r\n" );
document.write( "   Put the other factor in the lower left box and put an x after it,\r\n" );
document.write( "   (or whatever the variable letter happens to be)\r\n" );
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document.write( "   They're both 4, so put 4x in both boxes:\r\n" );
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document.write( "x²-8x+16\r\n" );
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document.write( "7. Give the larger of those two the same sign as the middle term.\r\n" );
document.write( "   If the last term is positive, give the smaller the same sign.\r\n" );
document.write( "   If the last term is negative, give the smaller the opposite sign.\r\n" );
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document.write( "They're both the same, so pick one and give it a - sign, since\r\n" );
document.write( "the middle term's sign is -. Give the other one a - sign also, since\r\n" );
document.write( "the last term is +.\r\n" );
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document.write( "8.  Put the GCF of the top row to the left of the top row.\r\n" );
document.write( "    Put the GCF of the bottom row to the left of the bottom row.\r\n" );
document.write( "    If the bottom row begins with a -, give the GCF a -\r\n" );
document.write( "    Put the GCF of the left column above the left column.\r\n" );
document.write( "    Put the GCF of the right column above the right column.\r\n" );
document.write( "    If the right column begins with a -, give the GCF a -,\r\n" );
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document.write( "9.  Use the factors outside to make two binomials:\r\n" );
document.write( "     (x-4)(x-4)\r\n" );
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document.write( "That's it.  However since they are the same binomial, write just one\r\n" );
document.write( "of them squared:\r\n" );
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document.write( "Answer:  (x-4)²   \r\n" );
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document.write( "Edwin
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