document.write( "Question 70426: The length of a rectangle is 8in more than twice its wodth. If the perimeter of the rectangle is 64in, find the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Multiple choice:
\n" ); document.write( "a) 10in
\n" ); document.write( "b) 7in
\n" ); document.write( "c) 8in
\n" ); document.write( "d) 9in\r
\n" ); document.write( "\n" ); document.write( "How do I get this to figure out one of these answers? Thank you
\n" ); document.write( "

Algebra.Com's Answer #50291 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
LENGTH=(2W+8)
\n" ); document.write( "PERIMETER IS=2L+2W
\n" ); document.write( "64=2(2W+8)+2W
\n" ); document.write( "64=4W+16+2W
\n" ); document.write( "64-16=6W
\n" ); document.write( "48=6W
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 FOR THE WIDTH THUS THE LENGTH IS
\n" ); document.write( "2*8+8
\n" ); document.write( "16+8
\n" ); document.write( "24 IS THE LENGTH
\n" ); document.write( "PROOF
\n" ); document.write( "2*24+2*8=64
\n" ); document.write( "48+16=64
\n" ); document.write( "64=64
\n" ); document.write( "
\n" );