document.write( "Question 70426: The length of a rectangle is 8in more than twice its wodth. If the perimeter of the rectangle is 64in, find the width of the rectangle.\r
\n" );
document.write( "\n" );
document.write( "Multiple choice:
\n" );
document.write( "a) 10in
\n" );
document.write( "b) 7in
\n" );
document.write( "c) 8in
\n" );
document.write( "d) 9in\r
\n" );
document.write( "\n" );
document.write( "How do I get this to figure out one of these answers? Thank you \n" );
document.write( "
Algebra.Com's Answer #50291 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! LENGTH=(2W+8) \n" ); document.write( "PERIMETER IS=2L+2W \n" ); document.write( "64=2(2W+8)+2W \n" ); document.write( "64=4W+16+2W \n" ); document.write( "64-16=6W \n" ); document.write( "48=6W \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 FOR THE WIDTH THUS THE LENGTH IS \n" ); document.write( "2*8+8 \n" ); document.write( "16+8 \n" ); document.write( "24 IS THE LENGTH \n" ); document.write( "PROOF \n" ); document.write( "2*24+2*8=64 \n" ); document.write( "48+16=64 \n" ); document.write( "64=64 \n" ); document.write( " |