document.write( "Question 834165: solve using the elimination method.
\n" ); document.write( "3r-7s=-32
\n" ); document.write( "7r+3s=22 \n" ); document.write( "
Algebra.Com's Answer #502902 by ankor@dixie-net.com(22740)\"\" \"About 
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solve using the elimination method.
\n" ); document.write( "3r - 7s =-32
\n" ); document.write( "7r + 3s = 22
\n" ); document.write( "multiply the 1st equation by 3, and the 2nd equation by 7, resulting in:
\n" ); document.write( " 9r - 21s = -96
\n" ); document.write( "49r + 21s = 154
\n" ); document.write( "-------------------Adding eliminates s, find r
\n" ); document.write( "58r + 0 = 58
\n" ); document.write( "r = 58/58
\n" ); document.write( "r = 1
\n" ); document.write( "Find s using the 2nd original equation, replace r with 1
\n" ); document.write( "7 + 3s = 22
\n" ); document.write( "3s = 22-7
\n" ); document.write( "3s = 15
\n" ); document.write( "s = 15/3
\n" ); document.write( "s = 5
\n" ); document.write( "Check solutions in the original 1st equation
\n" ); document.write( "3(1) - 7(5) =
\n" ); document.write( "3 - 35 = -32 \n" ); document.write( "
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