document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834288>Question 834288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: CD bisects AB <BR>\n" );
document.write( "       CD perpendicular to AB\r<BR>\n" );
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document.write( "Prove: CA is congruent to CB </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502885 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since cd is perpendicular to AB we have two right triangles<BR>\n" );
document.write( "cad and cbd\r<BR>\n" );
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document.write( "Since cd bisects ab then ad =db\r<BR>\n" );
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document.write( "we have <BR>\n" );
document.write( "ad^2+cd^2=ca^2<BR>\n" );
document.write( "and<BR>\n" );
document.write( "db^2+cd^2=cb^2<BR>\n" );
document.write( "but since<BR>\n" );
document.write( "ad=db then <BR>\n" );
document.write( "ad^2=db^2<BR>\n" );
document.write( "therefore <BR>\n" );
document.write( "ad^2+cd^2=db^2+cd^2<BR>\n" );
document.write( "hence<BR>\n" );
document.write( "ca^2=cb^2\r<BR>\n" );
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document.write( "therefore<BR>\n" );
document.write( " ca=cb\r<BR>\n" );
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document.write( "QED\r<BR>\n" );
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document.write( " </SPAN>\n" );
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