document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=834201>Question 834201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the running time for movie A is 31 minutes more than twice the running time for movie B. If the running time for movie A is subtracted from triple the running time for movie B, the result is 63 minutes. Find the running times for each movie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502855 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the running time for movie A is 31 minutes more than twice the running time for movie B. If the running time for movie A is subtracted from triple the running time for movie B, the result is 63 minutes. Find the running times for each movie<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "A = 2B+31<BR>\n" );
document.write( "3B-A = 63<BR>\n" );
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document.write( "Substitute for \"A\" and solve for \"B\":<BR>\n" );
document.write( "3B -(2B+31) = 63<BR>\n" );
document.write( "3B - 2B - 31 = 63<BR>\n" );
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document.write( "B = 94 minutes<BR>\n" );
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document.write( "A = 2B+31 = 2*94+31 = 219 minutes<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );