document.write( "Question 834119: Dad is seven times as old as his son. 10 years later, he will be three times as old as his son. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #502825 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \"Dad is seven times as old as his son\" ---> D = 7S\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"10 years later, he will be three times as old as his son\" ---> D+10 = 3(S+10)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D+10 = 3(S+10)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7S+10 = 3(S+10)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7S+10 = 3S+30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7S = 3S+30-10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7S-3S = 30-10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4S = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 20/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 5 <--- The son is 5 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D = 7S\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D = 7*5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D = 35 <---- The dad is 35 years old. \n" ); document.write( " |