document.write( "Question 834083: Ron takes two hr more then Paul to mow the lawn working together they can mow the lawn in 5 hr how long does it take each of them working alone? \n" ); document.write( "
Algebra.Com's Answer #502817 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Let t be the time for Paul to do the job alone.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_______________work rate________time__________job \n" ); document.write( "Ron___________(___)_____________t+2___________1 \n" ); document.write( "Paul__________(___)______________t____________1 \n" ); document.write( "Together______(___)______________5_____________1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rate*Time=Job, fill in the missing rate information.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_______________work rate________time__________job \n" ); document.write( "Ron___________1/(t+2)_____________t+2___________1 \n" ); document.write( "Paul__________1/t_________________t____________1 \n" ); document.write( "Together______1/5_________________5_____________1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The rates of both working together are simply additive. Solve for t. Use it to compute each person's rate. \n" ); document.write( " \n" ); document.write( " |