document.write( "Question 834059: Train a left the station at 7 a.m. And is traveling at a rate of 56 miles per hour. Train b left the same station at 8 AM traveling on a parallel track at a speed of 72 miles per hour. At what time will train b catch up to train a? \n" ); document.write( "
Algebra.Com's Answer #502810 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "______________speed___________time quantity____________distance \n" ); document.write( "train a_______56______________t+1______________________d \n" ); document.write( "train b_______72______________t________________________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The faster train travels for less time, so you see train b had traveled t hours but train a, the slower train, had to travel for t+1 hours. The time quantity between 7AM and 8AM is 1 hour. Both trains reach some identical travel distance, d. The unknowns are d and t.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rate*Time=Distance, the uniform rates equation for travel.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Equate the two expressions for d and solve for t. \n" ); document.write( " |