document.write( "Question 834023: Exam scores are normally distributed with a mean of 81 and a standard deviation of 9.\r
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document.write( "a) What is the minimum score one must have to be in the top 4% of the students taking the exam?\r
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document.write( "b) What percentage of scores are below 90?\r
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document.write( "c) What percentage of scores are above 45?\r
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document.write( "d) If 30 people take this exam, how many would you expect to get above a 93%?\r
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document.write( "e) If you have a test score in the 45th percentile, what is its z-score?\r
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document.write( "f) What is the z-score and percentile for an exam score 1.2 standard deviations below the mean? \n" );
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Algebra.Com's Answer #502797 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Exam scores are normally distributed with a mean of 81 \n" ); document.write( "and a standard deviation of 9. \n" ); document.write( "a) What is the minimum score one must have to be in the top 4% of the students taking the exam? \n" ); document.write( "Find the z-score with a right tail of 4%: \n" ); document.write( "invNorm(0.96) = 1.7507 \n" ); document.write( "--- \n" ); document.write( "Find the corresponding score: 81+1.7507*9 = 96.76 \n" ); document.write( "---------------------------------------------------------- \n" ); document.write( "b) What percentage of scores are below 90? \n" ); document.write( "z(90) = (90-81)/9 = 1 \n" ); document.write( "P(x < 90) = P(z < 1) = 0.8413 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "c) What percentage of scores are above 45? \n" ); document.write( "Find z(45) then find the Probability z is above that z value. \n" ); document.write( "------------------------ \n" ); document.write( "d) If 30 people take this exam, how many would you expect to get above a 93%? \n" ); document.write( "Ans:0.07*30 = 2.1 \n" ); document.write( "---------------------------- \n" ); document.write( "e) If you have a test score in the 45th percentile, what is its z-score? \n" ); document.write( "invNorm(0.45) = -0.1257 \n" ); document.write( "---------------------------- \n" ); document.write( "f) What is the z-score and percentile for an exam score 1.2 standard deviations below the mean? \n" ); document.write( "z = -1.2 \n" ); document.write( "score = 81-1.2*9 = 70.2 \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |