document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833993>Question 833993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 4 consecutive integers such that twice the sum of the first and third is 11 greater than 3 times the second.\r<BR>\n" );
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document.write( "Thank you -  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502777 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find 4 consecutive integers such that twice the sum of the first and third is 11 greater than 3 times the second. <BR>\n" );
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document.write( "1st: x-2<BR>\n" );
document.write( "2nd: x-1<BR>\n" );
document.write( "3rd: x<BR>\n" );
document.write( "4th: x+1<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "2(x-2 + x) = 3(x-1)+11<BR>\n" );
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document.write( "2(2x-2) = 3x-3+11<BR>\n" );
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document.write( "4x-4 = 3x+8<BR>\n" );
document.write( "x = 12<BR>\n" );
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document.write( "1st: x-2 = 10<BR>\n" );
document.write( "2nd: 11<BR>\n" );
document.write( "3rd: 12<BR>\n" );
document.write( "4th: 13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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