document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=833950>Question 833950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle.\r<BR>\n" );
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document.write( "P=2L+2W\r<BR>\n" );
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document.write( "46=2L+2(2L-3)<BR>\n" );
document.write( "46=2L+4L-6<BR>\n" );
document.write( "52=6L<BR>\n" );
document.write( "L=8.66\r<BR>\n" );
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document.write( "46=2(8.66)+2(2(8.66)-3)<BR>\n" );
document.write( "46=17.32+2(17.32-3)<BR>\n" );
document.write( "46=17.32+2(14.32)<BR>\n" );
document.write( "46=17.32+28.64<BR>\n" );
document.write( "46=45.96 ft.\r<BR>\n" );
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document.write( "L=8.66 ft.   W=14.32 ft.\r<BR>\n" );
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document.write( "I'm not sure if this is correct since I kept getting decimals. <BR>\n" );
document.write( "Thanks!!!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #502766 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=502766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8.6667 is correct or you can leave it as  a mixed number 8 2/3 </SPAN>\n" );
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