document.write( "Question 833960: When the length of a rectangle is increased by 20% and the width increased by
\n" ); document.write( "10%, by what percent is the area increased? \n" ); document.write( "
Algebra.Com's Answer #502761 by DrBeeee(684)\"\" \"About 
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Let l = length of original rectangle
\n" ); document.write( "Let w = width of original rectangle
\n" ); document.write( "Let a = lw = area of original rectangle
\n" ); document.write( "Let L = length of expanded rectangle
\n" ); document.write( "(1) L = l + 0.20*l or
\n" ); document.write( "(2) L = 1.20*l
\n" ); document.write( "Let W = width of expanded rectangle
\n" ); document.write( "(3) W = w + 0.10*w or
\n" ); document.write( "(4) W = 1.1*w
\n" ); document.write( "Let A = area of expanded rectangle
\n" ); document.write( "(5) A = L*W or
\n" ); document.write( "(6) A = (1.2l)*(1.1w) or
\n" ); document.write( "(7) A = (1.2*1.1)*lw or
\n" ); document.write( "(8) A = (1.32)*a or
\n" ); document.write( "(9) A = a + 0.32*a or
\n" ); document.write( "(10) A = a + 32% of a
\n" ); document.write( "Answer: The area of the expanded rectangle is 32% larger than the original rectangle.\r
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